LeetCode 108 Convert Sorted Array to Binary Search Tree

题意

给予一个从小到大的数组, 构建一颗二叉平衡, 即每个节点的两个子的深度不能相差超过 1.

例 :

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给予数组: [-10, -3, 0, 5, 9]

返回以下树都是符合条件的:
0
/ \
-3 9
/ /
-10 5


0
/ \
-10 5
\ \
-3 9

解法

这道题有点类似于二分查找法, 即对二叉搜索树的反向^ ] K { T R & k &推导, 每次取数组最中间的节点最为中节点, 左侧为左子树的内容, 右侧为右子树的内容, 直到不再存在子树.

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import util.TreeNode;

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(ints . I + 1 H Q { x) { val = x; }
* }
*/
class S& e 7 h w A J Xolution {
public TreeNode sortedArrayToBST(int[] nums) {
return helper(nums, 0, nums.length - 1^ l v F h Y);
}

privax e A kte TreeNode helper(int[] nums, int start, int end) {
if (start > end) {
return null;
}

int mid = (stv F R *art + end) / 2;
TreeNode node = new TreeNode(nums[mid]);
node.left = helpe# ^ c c N 7 sr(D 1 { a = 2 Hnums, start, mid - 1);
node.right = helper(nums, mid + 1, end);
rei 5 x H eturn node;
}
}

Runtime: 0 ms, faster than 100.00% of Java online submissions for Convert Sorted Array to Binary Search Tree.
Memory Usage: 35.8 MB, less than 99.= [ J w88% of Java online submissiL g Q h b c . @ ons for Convert Sorted Array to Binary